2 Blocks at the same Vector... how to avoid?

Questions & Answers
1

Hello guys,

I have a problem with this code:

    public int counterA = 0;
    public int counterB = 0;

    void FixedUpdate()
    {
        counterA = 0;
        counterB = 0;
        Vector3 vec = new Vector3();
        foreach (GameObject obj in GameObject.FindGameObjectsWithTag("Block"))
        {
            counterA++;
            foreach (GameObject obj2 in GameObject.FindGameObjectsWithTag("Block"))
            {
                counterB++;
                vec = new Vector3(obj2.transform.position.x,obj2.transform.position.y,obj2.transform.position.z);
            }
            if ((counterA != counterB) && (new Vector3(obj.transform.position.x,obj.transform.position.y,obj.transform.position.z) == vec))
                {
                    DestroyObject(obj);
                }
        }
    }

This code should delete one Block if he has the same Position as any other already placed block with the Tag “Block”.
Problem: It always deletes both Blocks. And i can only place one block. If i place another Block anywhere else it gets deleted immediatly

Hope you can help me…

Greetings,
Markus

2

Ok i found the mistake. I have to reset the CounterB in the first foreach, otherwise it keeps counting…

thx anyway