Add Force: Increase Speed of Ball periodically

Questions & Answers
1

Hi, I am making a 4 player pong game, and I want the ball to increase speed every 10 seconds. heres the code i have so far, im just not sure what to add to it to achieve this.

var temp : Vector3;


function Start() 
{
	
	gameObject.rigidbody.AddForce(500,0,500);
 }

function OnCollisionEnter(col : Collision)
{
	temp = gameObject.rigidbody.Velocity;
	Debug.Log("X: " + temp.x + " Y: " + temp.y);
	if(temp.x > 0)
	{
		gameObject.rigidbody.AddForce(-1000, 0, 0);
	}
	else if(temp.x <0)
	{
		gameObject.rigidbody.AddForce(1000, 0, 0);
	}
	if(temp.z > 0)
	{
		gameObject.rigidbody.AddForce(0, 0, -1000);
	}
	else if(temp.z <0)
	{
		gameObject.rigidbody.AddForce(0, 0, 1000);
	}
}


function Update()
{
var temp : Vector3 = gameObject.rigidbody.Velocity;
	if(temp.x > 0)
	{
		gameObject.rigidbody.AddForce(-1500, 0, 0);
	}
	else if(temp.x <0)
	{
		gameObject.rigidbody.AddForce(1500, 0, 0);
	}
	if(temp.z > 0)
	{
		gameObject.rigidbody.AddForce(0, 0, -1500);
	}
	else if(temp.z <0)
	{
		gameObject.rigidbody.AddForce(0, 0, 1500);
	}
}
    enter code here
3

Instead of doing that super-convoluted thing there, why not just use something like this?

rigidbody.AddForce(rigidbody.velocity.normalized * forceAmount, ForceMode.Impulse);

This will add force based on the current velocity of the object. Otherwise, just rely on the physics engine for collisions and reflections.

4

Set one Variable time and take Time.time after every 10 sec set it like

rigidbody.velocity = new Vector3(rigidbody.velocity.x * speed, 0, rigidbody.velocity.z * speed)

May Be it will work once try…

2

If you’re having issue with the time, set up a time variable and add ten seconds to it. Whenever Time.time is greater than your time variable, increase the velocity by whatever and reset your time variable by 10 seconds. That or do an ienumerator function.

If you’re having issue with adding force I’d create a speed variable and use that to drive the movement. Someone else can probably give you more exact instructions for that.