array problems : error operator cannot be used with a left hand side of type int and a right hand side of type object

Questions & Answers
1

var uRate= new Array();
uRate[0]=5000/expIncrement;
uRate[1]=10000/expIncrement;
uRate[2]=25000/expIncrement;
uRate[3]=75000/expIncrement;
uRate[4]=10000/expIncrement;
uRate[5]=250000/expIncrement;
uRate[6]=500000/expIncrement;
uRate[7]=1000000/expIncrement;
var uName=0;
var uNameString=“”;
if(num>=0&&num<uRate[0])
{
uName=(uRate[0]-num);
uNameString=“RoadSide Trader”;

	}

any idea?

2

Don’t ever use Array for anything ever. List is far superior (and has all the same functions).

Try changing your var line to be:

var uRate : List.< float > new List.< float >();

You may need to .Add your values instead of just setting them, I’m not certain.

3

You’ll have to cast uRate[0] (or any other access) to an int

    if(num>=0&&num<(int)uRate[0])
    {
        uName=(((int)uRate[0])-num); 
        uNameString="RoadSide Trader"; 
    }

I would also recommend using a typed array (or list as mentioned in the other answer)

var uRate = new int[8];

//---or---

var uRate = new List.<int> ( );

Either of those would avoid the need for casting.

4

ok thanks ^^