C# Unity 2D Respawning

Questions & Answers
1

I have this current script but whenever I try it works fine but my z position is -1 I need it to be 2 help either need a better re spawn method or a fix

    IEnumerator respawn()
    {
        player.GetComponent<Transform>().position = new Vector3(checkpx, 1, 2);
        Destroy(GetComponent<Rigidbody2D>());
        yield return new WaitForSeconds(1);
        player.AddComponent<Rigidbody2D>();
        player.GetComponent<Transform>().position = new Vector2(checkpx, 2);
        Debug.Log("RIP DEAD");
        health = 3;

    }
2

EDIT:

Sorry just noticed to you never have to get the transform as a component, all MonoBehaviours have it available by default. So this line:

player.GetComponentTransform.position = new Vector2(checkpx, 2);

line should be changed to:

player.transform.position = new Vector3(checkpx, 2,2);

because unity is a 3d engine even the 2d objects can be positioned in 3d. So when you make a 2d game in unity it is really a 2.5d game, that is why there is more overhead than a 2d game engine. The closest thing to actual 2d is using the canvas. You can also set the position of something after you instantiate it, which is how i usually do it, because the instantiation and setting the position will happen in the same frame you can set the position and other attributes after you instantiate it.

3

I just take away full control until the player is correctly placed

   public bool canmove;

   if (canmove) {
   // Some movement script
   }

    IEnumerator respawn()
    {
        Debug.Log("RIP DEAD");
        canmove = false;
        player.transform.position = new Vector3(checkpx, 2, 2);
        Destroy(GetComponent<Rigidbody2D>());
        yield return new WaitForSeconds(.4f);
        player.AddComponent<Rigidbody2D>();
        player.transform.position = new Vector3(checkpx, 2, 2);
        health = 3;
        yield return new WaitForSeconds(.4f);
        canmove = true;

    }