Can some one please explain this scrip to me :)

[MC_HALO]

Hello guys can you explain this script to me please :

if(headBobEnabled) {
		
		var percentage = Mathf.Min(1, Mathf.Abs(Input.GetAxis("Vertical")) + Mathf.Abs(Input.GetAxis("Horizontal")));
		
		
		var desiredPosX = initialLocalPos.x + headBobDistance.x * Mathf.Sin(Time.time * headBobSpeed + Mathf.PI/2);
		//Blend between stationary and desired x position
		t.localPosition.x = (initialLocalPos.x * (1 - percentage)) + (desiredPosX * (percentage));
	
}

i want to know what the Mathf.PI/ 2 is doing and what
var percentage = Mathf.Min(1, Mathf.Abs(Input.GetAxis(“Vertical”)) + Mathf.Abs(Input.GetAxis(“Horizontal”)));

what is 1 needed for right before the mathf.min? please explain this in a simple way if possible thank you

[ckfinite]

Okay. Starting with your first question, Mathf.Pi/2 is a value in radians for 90-degrees. This is important in this case since the mathematicial function Sin repeats every 2Pi. This is important because without the offset, sin would return 0 at time 0. With this setup, it will return 1 at time zero.

The answer to your second question is caused by the nature of the math you are doing. It simply gets a speed that is between 0 and 1, and if the speed is greater than 1 (i.e. if you have a 60% vertical and a 50% horizontal deflection), it reduces the total sum to one. Clamping the value to between 0 and 1 would be more clear.

[Santa]

percentage = Mathf.Min(1, Mathf.Abs(Input.GetAxis(“Vertical”)) + Mathf.Abs(Input.GetAxis(“Horizontal”)));

Is used to cut the percentage to the maximum of 1. I.e. if “Vertical+Horizontal” is more than 1 then “Min” will return “1”.

Mathf.PI/ 2

Is used to shift the “Sin” value. Half of PI is equal to 90 degrees. In general “Sin” here is used as some coefficient to position. To shift desired position smooth.