carl.transform.position = characterPosition -- how to set to this specific position but -3 on x axis?

Hello - when my third person controller walks into a collider, he is destroyed, and a new third person controller is set to active in the exact same position, but rotated 180 degrees.

This script works - but I would like the character to be set in the same position as the first third person controller, but -3 on the x axis.
I just can’t work out how to script this correctly - I tried this line:

carl.transform.position(new Vector3(characterPosition-3, characterPosition, characterPosition));

But this came up with a lot of errors. How do I transform a character to this character position, but -3 on the x axis?

This is my SetCharacterToActive script (JavaScript):

var carl : GameObject;
var vincentCamera : GameObject;
var thirdPerson : GameObject;
var script : SwitchCharacters;
var playerGO : GameObject;  //Should be filled with the GameObject the SwitchCharacters script is attached to
private var hasPlayed = false;

var characterPosition : Vector3;

function Start () {

carl.SetActive (false);
vincentCamera.SetActive (false);

}


function OnTriggerEnter () {


if (!hasPlayed&&!thirdPerson.active){

characterPosition = GetComponent(DestroyCharacterVincent).firstCharacterPosition;

carl.transform.position = characterPosition;
carl.transform.Rotate(new Vector3(0, 180, 0));


carl.SetActive (true);
vincentCamera.SetActive (true);



script.cam02 = carl.Find("VincentCamera");


script = playerGO.GetComponent(SwitchCharacters);
script.player02 = carl;


hasPlayed = true;

}

}

Thanks so much, Laurien

Well, you’re forgetting the x,y and z.
This is the right form

carl.transform.position(new Vector3(characterPosition.x-3, characterPosition.y, characterPosition.z))

hi

Instead of using

carl.transform.position(new Vector3(characterPosition-3, characterPosition, characterPosition));

try

carl.transform.position = Vector3(characterPosition.x - 3, characterPosition.y, characterPosition.z);

E: The position property is of course no method, thanks to Scribe