Error with code

Unity Engine
1

hello all, i’m having some problem with my code. can anyone fix it? it says “A field initializer cannot reference the nonstatic field, method, or property `BlockSpawn.rnd’”
i am just a beginner on unity. thanks

using UnityEngine;
using System.Collections;

public class BlockSpawn : MonoBehaviour
{
public GameObject[ ] Sprite2_0;
public Vector3 spawnValues;
public int blockcount;
Random rnd = new Random();
int randomBlockNumber = rnd.Next(1, 6);
private int numberOfColumns = 33;
private int numberOfRows = 23;

void Start()
{
StartCouroutine(SpawnWaves());
}

IEnumerator SpawnWaves ()
{
while (true)
{
for (int i = 0; i < numberOfColumns; i++)
{
for (int a = 0; a < randomBlockNumber; a++)
{
Vector3 spawnPosition = new Vector3 (Random.Range (spawnValues.x * numberOfColumns, spawnValues.y * numberOfRows));
}
}
}
}
}

2

doesnt’ work.

int randomBlockNumber = rnd.Next(1, 6);

make

int randomBlockNumber;

and than

void Start()
{
randomBlockNumber = UnityEngine.Random.Range(1,6);
StartCouroutine(SpawnWaves());
}
3

i tried it and got “The type UnityEngine.Vector3' does not contain a constructor that takes 1’ arguments” and also "
The name `StartCouroutine’ does not exist in the current context"

4

Your vector 3 random is only bring back one number. A vector 3 needs 3 numbers seperated by commas.

5

“StartCoroutine” check spelling

new Vector3 (xValue, yValue, zValue)

6

what if it’s only for a 2D game, would i still need vector3

7

depends on how you build yor scene in unity.

but you would still need a second value for a Vector2

8

Out of curiosity have you downloaded & done the tutorials?

9

isn’t spawnValues.x and spawnValues.y the two values

10

You can use 2d & 3d stuff to build a 2d game. If you are using 2 points to determine where something is then it’s a vector2. You are creating a new vector3 which needs 3 numbers but all you are doing is creating a vector 3 that has the first number being a random number between those 2 values.

11

not in your code.

Vector3 spawnPosition = new Vector3 (Random.Range (spawnValues.x * numberOfColumns, spawnValues.y * numberOfRows));

Random.Range (spawnValues.x * numberOfColumns, spawnValues.y * numberOfRows)

Returns a random value between spawnValues.x * numberOfColumns and spawnValues.y * numberOfRows

so in the end you have, with your code,

Vector3 spawnPosition = new Vector3 (oneRandomIntValue);

why do you make Random.Range in your Vector, what do you intend?

12

to create random blocks in every column,

13

It won’t work that way, if the first random spot is x=1 then it will be put in 33(for example if your width is 33). If your grid is 30X30 & is located at 0,0,0 then you could try the x&y co-ords as a random between 0&31. You will need to do a while loop to check that it hasn’t spawned on top of another object that’s already placed. This will create x-blocks somewhere on the grid.

If you want to select from a number of items & place one of them on each x&y coordinate then the loop will be different as you increment along each x position up to the last one then increment the y position, reset x back to 0 & starte placing again. Repeat until you hit the y maximum as well.