How Can I Linear Interpolate (Lerp) in Local Space?

Questions & Answers
1

I’m trying to smooth the motion of my camera by using Lerp (I had previously been using Transform.translate). This has worked for panning my camera left and right, but I have my camera pitched downward at 45 degrees and I would like my scroll wheel to move the camera in Local Z (ie, along the camera view path).

Lerp cannot take Space.Self as an argument, so how can I achieve this?

(If possible a C# solution would be appreciated, but I can translate a JS answer to C#)

3

Solved.

You can get the local vector by using transform.InverseTransformDirection().

Vector3 relativeMoveVector = transform.InverseTransformDirection(moveVector);
myCamera.position = Vector3.Lerp(myCamera.position, myCamera.position + relativeMoveVector, Time.deltaTime * smoothingFactor);
2

Keep in mind that lerp is a really straight forward function. It’s “how much i do take from a, and how much do I take from b”. Thus, the space you’re working on is irrelevant. What you mean is a lerp between a position and that position minus a certain distance along it’s forward vector (here is the space.self). It’s up to you to find that a and that b. Then the wheel will control the t in Lerp(a, b, t).