How do you subtract a number from the Z position each time an object is destroyed?

Questions & Answers
1

I need the camera to zoom out -0.05 after each time an object is destroyed. I have a camera script and destroy object script. The camera script is below. Everything works fine other than zooming out. I would think the zoomOut function below would do it by subtracting from the z position, but it’s not working. Any help would be appreciated!

   //Camera Script
    public float xMin = -50f;
    public float yMin = -50f;
    public float xMax = 50f;
    public float yMax = 50f;
    private Transform target;
    public destroy dotDestroy;

.

    void Start(){
        target = GameObject.Find("Player").transform;
    }

void LateUpdate()

{

transform.position = new Vector3(Mathf.Clamp(target.position.x, xMin, xMax), Mathf.Clamp(target.position.y, yMin, yMax), transform.position.z);

}

    public void zoomOut()
    {
        if (dotDestroy)
        {
            transform.localPosition -= new Vector3(0, 0, -0.05f);
        }
    }
2

The problem is that you are subtracting the “z” position to “-.05f” every time you call “zoomOut()”. The z will add because of the double negative. Try this instead:

 public void zoomOut()
     {
         if (dotDestroy)
         {
             transform.localPosition = new Vector3( transform.localPosition.x ,  transform.localPosition .y,  transform.localPosition.z -0.05f);
         }
     }

AND you might wanna try putting the code into “FixedUpdate()” instead of “LateUpdate()”