How to generate a random vector3 with the same z distance relative to a map with rotation?

Questions & Answers
1

How can I randomize the spawn location(x) of my gameobject while maintaining it’s z distance from the map? Doing a transform.position.z won’t do since the spawner and the map have a rotation.

Vector3 spawnLoc = new Vector3(Random.Range(minX, maxX), transform.position.y, ?????);

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2

Does that mean your map is moving and rotating?
Why not use relative positioning? If your spawned object is set as a child of the map, you won’t need to know the rotation or position of the map. Just the relative position of your object map wise.

3

Why don’t you keep the map and spawner rotation at 0 and just rotate the camera? Same visual effect, easier maths.

4

Hi guys solved it myself this is what I did.

    public float minX = -7.45f;
    public float maxX = -1.45f;
    float prevX;
    float prevZ;

    void Start () {
        prevX = transform.position.x;
        prevZ = transform.position.z;        
	}

 void Generate() {

        float newX = Random.Range(minX, maxX);
        float newZ = ((prevX - newX) - prevZ) * -1;

        prevX = newX;
        prevZ = newZ;

        Vector3 spawnLoc = new Vector3(newX, transform.position.y, newZ);
    }