How to get new position of object based on start point, distance and angle?

Questions & Answers
1

How to get position based on start point, distance and angle?

Here is my implementation:

Vector3 GetObjectPosition(Vector3 startPoint, float distance, float angle)
{
	Vector3 newPos = new Vector3 (startPoint.x, startPoint.y);
	handObject.transform.Rotate (newPos, angle);
	newPos = handObject.transform.forward * distance;

	return newPos;
}
void Update () 
{
	Vector3 mousePos = Camera.main.ScreenToWorldPoint(Input.mousePosition);
	mousePos.z = 0;
	float angle = Vector2.Angle(this.transform.position, mousePos);

	Vector3 handPos = UpdateHandPosition (this.transform.position, 10.0f, angle);
	handObject.transform.position = handPos;
	print (handPos);
}

As result it blinks(moves very fast) and doesn’t work properly

2

you can use SOH CAH TOA to get a direction vector, multiply it by distance then add it to startPoint

so your direction vector is something like Vector2(x = Mathf.Cos(angle), y = Mathf.Sin(angle))

convert your answer to degrees or keep in radians depending on how your angle is used

3

Vector2 GetObjectPosition(Vector2 startPoint, float distance, float angle){

    transform point;  //i don't remember how to rotate a vector2 so i used a transform
    point.position = startPoint;  //i'm sure there's a function to rotate a vector2
    point.rotate(angle);  //now it's pointing to the desired new location

    point.forward * distance;  //now walk forward that much of a distance
    //transform.forward is shorthand for (1,0,0). If your distance is 1.5f, it'll be(1.5f, 0, 0)

    return transform.point;

}