How to identify 2 decimal places?

Questions & Answers
1

Assume :-

List<double> countTime = new List<double>();

void Update()
{
     countTime.Add(Time.deltaTime);
}

void printAllNumbersWithOnly2Decimals()
{
     for(int i=0; i<countTime.Count; i++)
     {
          if(*numbers have 2 decimals in it*)
               then display it;
     }
}

Another example is arr[4] = {1.22, 1.333, 2.333, 2.22};
How to print only {1.22}, {2.22}?

2

I am by no means an expert or a computer scientist. So my explanation may be misleading or incorrect, but I will try to explain to the best of my ability.

One thing about floating point notation is that floats and doubles will never, or rarely only have 2 decimal places. Even if you set a double to 1.22, it may be stored in memory differently, It’s possible that the value will be stored as 1.22000000000001 instead. So this is something that needs to be considered.

//if numbers have 2 decimals in it then display it
void printAllNumbersWithOnly2Decimals()
{
	for(int i=0; i<countTime.Count; i++)
	{
		double difference = countTime _- double.Parse(countTime*.ToString("0.00"));*_

_ if (difference < 0) difference = -1; //Mathf.Abs() substitute_
_ if (difference <= double.Epsilon)_
_ {_
_ Debug.Log("Number: " + countTime + " has 2 decimal places");
 }
 }
 }*_

3

@ tapirlaut man you have blowed up my mind i been working all day long till i found out the way :

double [] countTime = new double[]{1.1,1.22,1.333,44} ;
void Start () 
{
	printAllNumbersWithOnly2Decimals ();
}

void printAllNumbersWithOnly2Decimals()
	{
		for(int i =0; i<countTime.Length;i++)
		{
			string e = countTime *.ToString ();*

  •  	if (e.Contains(".") && e.IndexOf(".") >= e.Length-3) //delete the > sine if you want only 2 decimal places but don't delete it if you want also 1 decimal places.*

  •  	{*

  •  		print (e);*

  •  	}*

  •  	else if(!e.Contains(".")) // make sure printing numbers that don't have decimal places delete if not necessary.*

  •  	{*

  •  		print (e);*

  •  	}*

  •  }*
  • }*