How to make a List or Array of functions with type Void

Questions & Answers
1

I’m trying to create a script that takes a random number and according to that number activates a function in a list or array. I can do this by doing a lot of conditional statements, however I was wondering if there was a simpler way of accomplishing the same task. I was thinking of

List<???> spawnRocks = new List<???>(); //Don't know which type I'm supposed to set  it as so that it takes objects of type Void

spawnRocks.Add (spawnRocks1());
spawnRocks.Add (SpawnRockes2());

//confirmed working
void spawnRocks1() {
   Instantiate something
}

void spawnRocks1() {
   Instantiate something
}
3

One solution here would be

    // define a delegate type to match the required method signature
    delegate void SpawnRocksMethod();

    void CreateList()
    {

        // create a list of delegate objects as placeholders for the methods.
        // note the methods must all be of type void with no parameters
        // that is they must all have the same signature.

        List<SpawnRocksMethod> spawnRocks = new List<SpawnRocksMethod>();

        spawnRocks.Add(spawnRocks1);
        spawnRocks.Add(spawnRocks2);

        // call a method ...
        spawnRocks[0]();
    }

    //confirmed working
    void spawnRocks1()
    {
        Instantiate something;
    }

    void spawnRocks2()
    {
        Instantiate something;
    }
2

This seems to contain a few solutions:

These two are also related and useful to know:

4

you could make a list of MonoBehaviors and then make as much scripts as you want for each function and call them like myMonoBehaviors[0]();.

5

as the accepted answer says, delegates would be the best way in this situation, because you know the return type. If you need a collection of methods with different return types, you would use an Action, which acts as a generic delegate.