How to open the door of the elevator by pressing the button when entering the collider?

Questions & Answers
1

I want the script for the elevator door

3

In this script you can send a trigger to the animator when the gameObject named “ElevatorGameObject” is inside the collider and you press the keyboard letter “E”

 void Start()
 {
     if(animator == null)
     {
         animator = GetComponent<Animator>();
         if(animator == null)
         {
             Debug.LogError("No animator component on this script!",gameObject);
         }
     }
 }

 void OnTriggerEnter(Collider triggerInfo)
 {

     if(triggerInfo.gameObject.name("ElevatorGameObjectName") && Input.GetKey(KeyCode.E)) 
     {
        //open elevator door
         animator.SetTrigger(onTriggerEnterParameterName);
     }
 }


 void OnTriggerExit(Collider triggerInfo) 
 {
     // do something else when exit
 }
}

We use the “triggerInfo” variable to store the trigger information so we can acces the gameObject properties, in this case we acces the name and compare it. we also use the “&&” operator as a condicion for also havin the letter E pressed

2

I would use something like this

void OnCollisionStay (Collions col)
{
        if (col.other == elevator)
        {
                 if (Button pressed)
                {
                //open elevator
                }
        }
}

so just if your player it colliding with the elevator and he presses the button it should open.
Note: This code isn’t perfect its just an exampe of how you could do it