How would I hide a gui button on press in C#?

Questions & Answers
1

I have two gui buttons and I managed to shut one off if not in use, but when I click it. Well, the new button shows up over top of the first button instead of completely turning off the first. I cut out the code that goes in mywindow because it’s a complete mess. But getting rid of the Show Window button is what I’m trying to do. I can’t seem to get it to go away after it shows the window.

public class ChangeColour : MonoBehaviour {
	private bool render = false;
	private Rect windowRect = new Rect (10, 100, 200, 200);
	public Texture2D colourTexture;
	public Renderer colouredCube;
	private Rect textureRect = new Rect (10, 50, 100, 100);
	bool opt = false;
	public void ShowWindow() {
		render = true;
	}
	
	public void HideWindow() {
		render = false;

	}
	
	public void OnGUI() {
				if (GUI.Button (new Rect (10, 20, 100, 20), "Show Window"))
						opt = !opt;
				ShowWindow ();

				if (opt) {

						if (GUI.Button (new Rect (10, 20, 100, 20), "Hide Window"))
								HideWindow ();
		
						if (render) {
								windowRect = GUI.Window (0, windowRect, DoMyWindow, "My Window");
						}
				}
		}
	
	public void DoMyWindow(int windowID) {
		
				}
		}

}
2

You could make use of booleans:

if (showButton){
    if (GUI.Button ( .... )) {
        //Do something
        showButton = false;
    }
}

Side note:

ShowWindow() is called every time OnGUI is called, not when the button is pressed, which means HideWindow() will only disable the renderer until the next OnGUI is called.

if ( .... )
    //Only reaches until the first semicolon (';')

if ( .... ) {
    //Everything inside here is a part of the 'if' statement
}