Instantiate on give position + extra distance on X axis

Questions & Answers
1

I’m trying to create a script wich randomly creates levels (sidescrolling) and i can get it to instantiate a random object on a given position, but i now want it to instantiate more than 1 object next to eachother (all random) but i can’t seem to figure out how to change x position (dynamically)

Here’s my source code:
var objs : GameObject;
var True = true;

var spawnLocation : Transform ;

if (True) {
    Instantiate(objs[(Random.Range(0, objs.Length))], spawnLocation.position, Quaternion.identity);
	Instantiate(objs[(Random.Range(0, objs.Length))], spawnLocation.position, Quaternion.identity);
}
2

turn the position : Vector3 of the Instantiate function from spawnLocation.position to spawnLocation.position + Vector3.right*offset. If you want a random distance use Random.Range. So it would look like this:

Instantiate(objs[(Random.Range(0, objs.Length))], spawnLocation.position + Vector3.right*Random.Range(-10,10), Quaternion.identity);