Opening an App from within an App Android

Questions & Answers
1

I've seen questions like this, but they were for iPhone/iPad. I'm trying to figure out the same thing except on Android.

I want to be running one game/app. And from within that app, I want to click a button, check to see if a certain app is installed, then run that app. Is there a way to do this on Android?

2

Any answer?

3

i know its late to answer but i might help some one else
there are two methods

  1. Use bundle id

          AndroidJavaClass up = new AndroidJavaClass("com.unity3d.player.UnityPlayer");
      AndroidJavaObject ca = up.GetStatic<AndroidJavaObject>("currentActivity");
      AndroidJavaObject packageManager = ca.Call<AndroidJavaObject>("getPackageManager");
      Debug.Log(" ********LaunchOtherApp ");
      AndroidJavaObject launchIntent = null;
      //if the app is installed, no errors. Else, doesn't get past next line
      try{
           launchIntent = packageManager.Call<AndroidJavaObject>("getLaunchIntentForPackage","com.Company.ProductName");

    //
    // ca.Call(“startActivity”,launchIntent);
    }catch(UnityException ex){
    Debug.Log(“exception”+ex.Message);
    }
    if(launchIntent == null)
    return false;
    return true;

  2. you can use application uri instead of application bundle id that way it will work for both platform

    Application.openurl(application uri);

Note its a uri not the url which will go inside the application.openurl .