Hi friends,
first, Unity 4.3 Get better. Thank you for all employees.
I’m designing a membership system. Using php. Okay, register and login.
I want one. Someone entered. Information show. How can we do this?
That is,
1: Introduction did . < " Okey. "
2: Information show. < " Needs to be done. "
(Test) Using php;
$userName = $_POST["myform_userName"];
$yaz = mysql_fetch_array(mysql_query("select * from profil where username='$userName'"));
$id = $yaz['id'];
$username = $yaz['username'];
$nick = $yaz['nick'];
Unity ;
public string userName= "";
form.AddField("myform_userName", userName);
User name entered.(Worked.) > How information will appear?
Waiting for help.
Thank You. And sorry, My english is a bit bad.
Hi,
You need to use WWW class with WWForm to fetch data from server. There is a good tutorial here .
-ikel
Thank you for your answer. That’s right.
“WWW” is required. But, For example, It’s complicated.
PartyNeverEnds:
“WWW” is required. But, For example, It’s complicated.
I don’t think it’s complicated. The script example in the documentation for WWWForm shows how you can upload high scores to a website. I know the example on the server is written in perl and not PHP, but it’s a complete, working example that is close to what you want to do. See:
http://docs.unity3d.com/Documentation/ScriptReference/WWWForm.html
The problem is still the same.
$userName = $_POST["myform_userName"];
$yaz = mysql_fetch_array(mysql_query("select * from profil where username='$userName'"));
$id = $yaz['id'];
$username = $yaz['username'];
$nick = $yaz['nick'];
The lower part of the code “echo” added.
Sample : echo $id;
When it comes to Unity. Code : idPublic = w.data; > It works. Entered as the user name, the id appears.
but,
do php code : echo $id; echo $nick;
Unity, Outcome : the same information, seems unified .
Picture ;
How can we show the other way?
when you echo try
echo $row[‘Name’] . “\n”;
to put each result on a new line.
