Prevent same numbers in a list

Scripting
1

Hello there,

I have a list of int values with random numbers from 1 to 11, Point is, I have to compare the first and second value in the list if one is higher or lower. Although, sometimes same values show up, like 5-5 or 10-10, which I don’t want to happen. I don’t want two values two show up one after another.

This is the code that I tried, could I get some directions ?

2

I don’t quite get your problem
Do you hace a problem with this:
1 4 6 3 6 2 8 7
Or this:
1 3 3 6 3 5 7 3 6 7 6 7 7

The first one should be easy to fix, using Linq (which is already in use by default) you can get a list with only unique elements if you use myList = myList.Distinct.ToList();

The second one is a little bit more complicated

int next = myList[myList.Count-1]; //this will be used to cache the value we need
for (int i = myList.Count - 2; i < 0; i++) { //Looping trough backwards
    if (next == myList[i]) //if they are the same
        myList.RemoveAt(i+1); //remove them
    next = myList[i]; //swap next with current
}

I’m going trough the list backwards, because then I can safely remove items from it without causing errors

1 Like
3

not efficient, I’ll be the first to admit, but as long as it is only going to be run once or once every game, should be fine.

//at top of file
using System.Collections.Generic;

//in script
int maxValue = 11;
int optionsNum = 20;
int[] numArray;

numArray = new int[optionsNum];
for(int i = 0; i < optionsNum; i++){
    List<int> tempOptions = new List<int>();//create list of options
    for(int j = 0; j < maxValue; j++){
        if(i > 0 && j != optionsNum[i-1])//check if previous and current are different
            tempOptions.Add(j);//populate list options
    }
    int chosen = UnityEngine.Random.Range(0,tempOptions.Count);//choose an option
    numArray[i] = tempOptions[chosen] + 1;//add option, +1 cause started with 0 instead of 1
}
1 Like