Random Exit Spawn

Questions & Answers
1

I am trying to make a game where the exit will randomly spawn. I have the idea that there will be 5 different locations that the exit can spawn in but I have no idea how to do this. The exits prefab name is “Exit”.

3

The easiest way to create it is to create an array of Vector3 for the position and then Instantiate with random value

something like(C#):

public Vector3[] spawnPoints;  // Array of Vector3 for position, set in the inspector
public GameObject exitPrefab;  // Exit prefab

void Start()
{
    int spwanPointIndex = Random.Range(0, spawnPoints.Length);
    Instantiate(exitPrefab, spawnPoints[spwanPointIndex], exitPrefab.transform.rotation);
}

the more “generic” way is to create a game object that will ground empty game objects that are located where the spawn points are and randomize that

should look like(again C#):

public GameObject spwanPointsObject; // The Parent Game Object for the spawn points objects
public GameObject exitPrefab;  // Exit prefab

void Start()
{
    Transform[] spawnPoints = spwanPointsObject.GetComponentsInChildren<Transform>();
    int spwanPointIndex = Random.Range(0, spawnPoints.Length);
    Instantiate(exitPrefab, spawnPoints[spwanPointIndex], exitPrefab.transform.rotation);
}

hope that helped

2

Here is a little script that I made (C#):

using UnityEngine;
using System.Collections;

public class EnemySpawner : MonoBehaviour {

	public GameObject Exit;

	void Start()
	{
		Vector3 position = new Vector2(Use Random Range and switch function to give the location);

		Instantiate(Exit, position, Quaternion.identity);
	}  }