real life:sin(2Pi)=0 unity Mathf.Sin(2Pi)=1.748456E-07

Questions & Answers
1

I really don’t understand what’s going on here, I was making a light intensity change based sin that didn’t want to work and I couldn’t figure out what was wrong until i tried simply using Mathf.Sin to 2Pi.

print("feed sine("+(2*Mathf.PI)+")= "+Mathf.Sin(2*Mathf.PI));

feed sine(6.283185)= 1.748456E-07

am I missing something here? can someone tell me where unity sine reaches its loop point?

2

If you are asking why it is not 0 it is about floating point accuracy. 1.748456E-07 is a number very close to zero and you should use epsilon when dealing with small floating point comparisons.