[SOLVED] Array Math Help

Scripting
1

This is more of a Javascript question than Unity related, but how could I add each element in Array B to each element in Array A each time the object goes off screen (all elements in both arrays are integers)?

I know a way to do it, but it would require doing the math for each individual element (which will exceed 50), so that’s really inefficient! But here’s how I know to do it:

var arrayA = [0, 10, 20, 30, 50];  // Each element here should equal 190 after arrayB is added
var arrayB = [190, 180, 170, 160, 150];  // Add this to each element in arrayA

function OnBecameInvisible ()
{
     arrayA[0] = arrayA[0] + arrayB[0];
     arrayA[1] = arrayA[1] + arrayB[1];
     arrayA[2] = arrayA[2] + arrayB[2];
     // And so on...
}

I’m sure there is a much more efficient way to do this, I just can’t figure it out.

Any help would be greatly appreciated!

- Chris

2

Use the for operator.

for (int i = 0; i < arrayA.Length; i++) {
arrayA[i] = arrayA[i] + arrayB[i];
}
1 Like
3

Looping them is one way…

Are the values always the same?

4

Thanks! This works! :slight_smile:

The values never change, so kru’s method works. I just needed to get each element in arrayA to equal 190 each time the object goes off screen.

5

If the values never change, why compute them at OnBecameInvisible, and not just 1 time and keep them (is what I was getting at) :slight_smile:

6

Oh, I misunderstood your question then!

Since I’m adding arrayB to each element in arrayA, each element in arrayA does change. But I need to add that 190 each time the object goes off screen because I want the object to jump ahead of the player (arrayA in this example was the preset x positions and arrayB was the amount to add to the x position). And depending on the object’s x position, the amount to add is different. :slight_smile:

7

Cool, I did start to consider possibilities after I responded… I got it :slight_smile: Glad ya got it working.

1 Like