(Solved) Double jumping

Questions & Answers
1

Hi, I’m simply trying to make my player able to double jump. So far I’ve been able to make my player able to jump once until it’s grounded again; then I tried to add a jump counter. However Unity gives me an error message on jumpCount +1;
Does anyone know what I’ve done wrong and how to fix this?

public float moveSpeed = 10f;
public float jumpForce = 50f;
int jumpCount = 1;

bool grounded = false;

void Update () 
{
//Jumping
if(jumpCount > 3 || grounded && Input.GetKeyDown(KeyCode.UpArrow))
	{
rigidbody2D.AddForce(new Vector2(0,jumpForce));
grounded = false;
jumpCount + 1;
	}
}
4

Usually, when jumping, you would want to zero out vertical velocity before adding force to counter any gravity. Next, you have 2 scenarios you want to watch for. Grounded & jumping, Airborn & jumping & candoublejump. So you want something like

if (jumpkeydown) {
  if (grounded) {
    rigidbody2D.velocity.y = 0;
    rigidbody2D.AddForce(new Vector2(0, jumpForce));
    candobulejump = true;
  } else {
    if (candoublejump) {
      candoublejump = false;
      rigidbody2D.velocity.y = 0;
      rigidbody2D.AddForce(new Vector2(0, jumpForce));
  }
}

values and descriptions may vary.

2

jumpCount > 3 || grounded

I think you mean less than, every time you jump the counter goes up, once it’s over 3 you can jump continuously. The error is also because you aren’t assigning that calculation to a variable, unlike Python you can’t just write ‘1+1’ and it will print the result. It will have to be ‘jumpCount = jumpCount + 1;’, or just += 1 or better yet jumpCount++.

3

You should try assigning jump count the +1 value. As you have it right now your variable is not being assigned your +1 value.

jumpCount = jumpCount + 1;