Sorting a List of objects with CompareTo

Questions & Answers
1

Hello, everyone!
My issue is, when I’m trying to Sort a List of RaycastHit2D’s with CompareTo method it doesn’t work.
Here’s the code part:

RaycastHit2D[] hits = Physics2D.BoxCastAll (caststart, playersize, 0f, castdir, c5_maxrange);
List<RaycastHit2D> hitList = new List<RaycastHit2D> ();
			hitList.AddRange (hits);
			Debug.Log ("Objects withOUT sorting");
			foreach (RaycastHit2D hit in hitList){
				Debug.Log (hit.collider.name + " " + hit.collider.bounds.max.x);
			}
//			return;
			hitList.Sort(delegate(RaycastHit2D x, RaycastHit2D y) {
				return(x.collider.bounds.max.x.CompareTo(y.collider.bounds.max.x));
			});
				Debug.Log ("Sorted Objects");
			foreach (RaycastHit2D hit in hits){
				Debug.Log (hit.collider.name + " " + hit.collider.bounds.max.x);
			}

And, unfortunately for me, the result before and after sorting doesn’t change. The reason I need this sorting is that BoxCastAll catches upper colliders first. then the lower ones, and when I start to check members in the list in reverse order I would like to check upper collider’s first. But basically, I’m trying to understand why Sort doesn’t actually sort. Thank you for the answer in advance.

2

Update.

Tried Using.System.Linq and after some struggling it worked! But only when OrderBy to a new list, which then cannot be sorted. Here’s the code in case somebody faces the same issue:

RaycastHit2D[] hits = Physics2D.BoxCastAll (caststart, playersize, 0f, castdir, c5_maxrange);
List<RaycastHit2D> hitList = hits.OrderBy(b=>b.collider.bounds.max.x).ThenBy(b=>b.collider.bounds.max.y).ToList();
Debug.Log ("Sorted Objects");
			foreach (RaycastHit2D hit in hitList){
				Debug.Log (hit.collider.name + " " + hit.collider.bounds.max.x);
			}
			return;

My mistake was simple adding RaycastHit2D result to a List and then applying for OrderBy method, which didn’t work either.

However, I’m still wondering why Sort(CompareTo) doesn’t work. I presume It is somehow connected to RaycastHit2D array type.