uploading screenshot to server

Questions & Answers
1

Hi guys

I am trying to upload a screenshot of my scene at the server using the WWW class. You can find here http://www.ionio.gr/~av200420/screen/screen.html my simple application. While clicking the cube an alert message says that the screenshot uploaded. I read that i should have a crossdomain.xml file, so, i uploaded here http://www.ionio.gr/~av200420/crossdomain.xml. In unity now I assign the screenshot url var screenShotURL= “http://www.ionio.gr/~av200420”; My problem is that unity says that everything is OK but i can find somewhere the screenshot to my server… Is there any problem with the assigned values or routs?

Thanks!

2

Your upload url doesn’t look like there’s anything on your server that can receive the upload? Do you have a serverside php script that saves the upload? It seems you forget that…

To take a screenshot and upload it there’s an example in the Unity docs.

Here’s a similar question where you can see how the serverside script can look like:

4

Unityscript:

var screenShotURL= "http://localhost:8888/upload_file.php";

function Start(){ 
	//print(Application.srcPath); 
}

function OnMouseDown() { 

	// We should only read the screen after all rendering is complete yield WaitForEndOfFrame();

	// Create a texture the size of the screen, RGB24 format
	var width = Screen.width;
	var height = Screen.height;
	var tex = new Texture2D( width, height, TextureFormat.RGB24, false );
	// Read screen contents into the texture
	tex.ReadPixels( Rect(0, 0, width, height), 0, 0 );
	tex.Apply();

	// Encode texture into PNG
	var bytes = tex.EncodeToPNG();
	Destroy( tex );

	// Create a Web Form
	var form = new WWWForm();
	form.AddField("frameCount", Time.frameCount.ToString());
	form.AddBinaryData("file", bytes, "screenShot.png", "image/png");

	// Upload to a cgi script    
	var w = WWW(screenShotURL, form);
	yield w;
	if (w.error != null){
	    print(w.error);
	    Application.ExternalCall( "debug", w.error);
	    //print(screenShotURL);
	}  
	else{
	    print("Finished Uploading Screenshot");
	    //print(screenShotURL);
	    Application.ExternalCall( "debug", "Finished Uploading Screenshot");
	}
}

PHP:

<?php 
	if ((($_FILES["file"]["type"] == "image/gif") || ($_FILES["file"]["type"] == "image/jpeg") || ($_FILES["file"]["type"] == "image/pjpeg")) && ($_FILES["file"]["size"] < 20000000000)) { if ($_FILES["file"]["error"] > 0) { echo "Return Code: " . $_FILES["file"]["error"] . "
	"; } else { echo "Upload: " . $_FILES["file"]["name"] . "
	"; echo "Type: " . $_FILES["file"]["type"] . "
	"; echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb
	"; echo "Temp file: " . $_FILES["file"]["tmp_name"] . "
	";

	if (file_exists("upload/" . $_FILES["file"]["name"]))
	  {
	  echo $_FILES["file"]["name"] . " already exists. ";
	  }
	else
	  {
	  move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $_FILES["file"]["name"]);
	  echo "Stored in: " . "upload/" . $_FILES["file"]["name"];
	  }
	}
	} else { echo "Invalid file"; } 
?>
3

I don’t know why but it doesn’t work yet. I am using this javascript

var screenShotURL= "http://localhost:8888/upload_file.php";

//var screenShotURL= “http://195.130.124.68/cgi-bin/screenshot.pl”;

function Start(){
//print(Application.srcPath);
}

function OnMouseDown() {
// We should only read the screen after all rendering is complete
yield WaitForEndOfFrame();

// Create a texture the size of the screen, RGB24 format
var width = Screen.width;
var height = Screen.height;
var tex = new Texture2D( width, height, TextureFormat.RGB24, false );
// Read screen contents into the texture
tex.ReadPixels( Rect(0, 0, width, height), 0, 0 );
tex.Apply();

// Encode texture into PNG
var bytes = tex.EncodeToPNG();
Destroy( tex );

// Create a Web Form
var form = new WWWForm();
form.AddField("frameCount", Time.frameCount.ToString());
form.AddBinaryData("fileUpload", bytes, "screenShot.png", "image/png");

// Upload to a cgi script    
var w = WWW(screenShotURL, form);
yield w;
if (w.error != null){
    print(w.error);
    Application.ExternalCall( "debug", w.error);
    //print(screenShotURL);
}  
else{
    print("Finished Uploading Screenshot");
    //print(screenShotURL);
    Application.ExternalCall( "debug", "Finished Uploading Screenshot");
}

}

and this php script

`

<?php if ((($_FILES["file"]["type"] == "image/gif") || ($_FILES["file"]["type"] == "image/jpeg") || ($_FILES["file"]["type"] == "image/pjpeg")) && ($_FILES["file"]["size"] < 20000000000)) { if ($_FILES["file"]["error"] > 0) { echo "Return Code: " . $_FILES["file"]["error"] . " "; } else { echo "Upload: " . $_FILES["file"]["name"] . " "; echo "Type: " . $_FILES["file"]["type"] . " "; echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb "; echo "Temp file: " . $_FILES["file"]["tmp_name"] . " "; if (file_exists("upload/" . $_FILES["file"]["name"])) { echo $_FILES["file"]["name"] . " already exists. "; } else { move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $_FILES["file"]["name"]); echo "Stored in: " . "upload/" . $_FILES["file"]["name"]; } } } else { echo "Invalid file"; } ?>

`

The program sais that the image uploaded… but there is no image inside the upload folder. Is there any wrong with the scripts? Do I want any other script in order to upload the screenshot???

Thanks again!