WARNING: This method could return default value implicitly.

Unity Engine
1

I got this warning on several functions. I read in Unity Answes that I should define the type that the function returns (I don’t know why, all the other functions work properly without type defining). So this is the function:

	function Axis(){
		if(type == SBIType.Key) return axisInterpolation;
		else if(type == SBIType.Axis){
			if(positive != ""  negative != "") return (Input.GetAxisRaw(positive) + Input.GetAxisRaw(negative))/2;
			else if(positive != "")  return Input.GetAxisRaw(positive)*1.0f;
			else if(negative != "")return Input.GetAxis(negative)*1.0f;
		} else return 0.0f;
	}

The warning won’t go away even if I define the return type:

function Axis() : float{ ...

Also if I make the function like that:

	function Axis() : float{
		var axis : float = 0.0f;
		if(type == SBIType.Key) axis = axisInterpolation;
		else if(type == SBIType.Axis){
			if(positive != ""  negative != "") axis = (Input.GetAxisRaw(positive) + Input.GetAxisRaw(negative))/2;
			else if(positive != "")  axis = Input.GetAxisRaw(positive)*1.0f;
			else if(negative != "")axis = Input.GetAxis(negative)*1.0f;
		} 
		return axis;
	}

The warning will disappear…

I want to know what’s actually happening here. Can somebody shed some light ? :slight_smile:
Cheers!

2

I wouldnt recommend you to make the returns inside of ifs, instead declare a “result” variable in the first line of the function, set it through out the function, and in the end return it.

3

You need an unconditional return value to clear that error. Your first example code using “else return 0.0f;” should just read as “return 0.0f;”. As “else return 0.0f;” can’t be evaluated to a fixed path and might branch to logic that won’t return anything which is what that error means.

4

Right! Thanks for the info! I never realised that. So I either have to use a result value or have an unconditional return.