InputField onValueChanged

Questions & Answers
1

I have a problem with calling onValueChanged on an InputField. It seems that currentText is updated before entering if case. Maybe I’m not seeing something. Any idea?

  • Example

  • First Step:

  • Inputfield: abcd

  • currentText: abcd

  • Second Step:

  • Remove “d”

  • currentText: abc

  • oldText: abc

       // Script 1
 public override void SetText(InputField _currentText)
 {

     if (currentText != null /*&& currentText != oldText*/)
     {
         Debug.Log("Current text: " + currentText.text);
         oldText = currentText;
         Debug.Log("Old text: " + oldText.text);
     }

     currentText = _currentText;

     Debug.Log("Current text: " + currentText.text);
 }

// Script 2
 private void Start()
 {
     editedText = new TextReceiver();
     textField.onValueChanged.AddListener(delegate { editedText.SetText(textField); });
 }
2

Simply because currentText,oldText, _currentText and textField are referencing the same inputfield. InputField is a class (reference type), so when you assign oldText = currentText, you are just telling oldText will reference the same InputField as currentText. and the following line textField.onValueChanged.AddListener(delegate { editedText.SetText(textField); }); won(t create a “new” inputfield each time the function is called. It will pass the same reference of the input field to the callback.

private string oldInputFieldValue;

public override void SetText(string newValue)
{
    Debug.Log("Old text: " + oldInputFieldValue);
    Debug.Log("Current text: " + newValue);
    oldInputFieldValue = newValue;
}

private void Start()
{
    editedText = new TextReceiver();
    textField.onValueChanged.AddListener(SetText);
}