How to use GetComponent<Rigidbody2D>()

Scripting
1

I’ve been trying my best to google but I honestly am still confused.

Trying to look up tutorials and get myself acquainted. First problem was trying to convert

rigidbody2D.velocity = new Vector2( 0, jumpHeight);

to

GetComponent()

I made rigidbody2D = GetComponent(), but then I get

UnityEngine.Component does not contain abstract definition for velocity and no extension method etc…

I just wanna make my character be able to jump up, any help is appreciated!

2

Try to cast the GetComponent() with an “as RigidBody2D” like that:
var rigidBody = GetComponent() as RigidBody2D;

It should work without the cast tho.

Could you send your code please?

3

Forgive me if this is wrong, shouldn’t you type cast your variable?

//<type>
RigidBody2D rigidbody2D = this.gameObject.GetComponent<Rigidbody2D>();

I read Unity - Scripting API: Rigidbody2D.velocity
It says velocity returns an x and y vector…
so

rigidbody2D.velocity = new Vector2( 0, jumpHeight);

should work. I’ll test this.

4

Don’t name your variable rigidbody2D. This is the same name as an existing deprecated property on MonoBehaviour. Call it anything else and the script will work.

3 Likes
5

Basically anything you get out of GameObject.GetComponent<>() needs to have it’s type casted.

1 Like
6

That is absolutely incorrect.

2 Likes
7

Assuming you do have a RigidyBody2D component on your object (I myself tend to miss this part quite often :smile: )
You may give it a force with a vector showing up using the AddForce function.

8

Stop mucking the thread up with wrong answers folks. @Kiwasi was correct

:slight_smile:

2 Likes
9

The generic version will always return the type passed in. That’s the whole point of the generic function and angle brackets. Casting is a total waste of time and performance.

The non generic version does return a component, and needs to be casted. But using the non generic version is limited to some special use cases. These are way beyond the OP at present.

Missing a RigidBody would throw a null reference error. Different problem.