Find out if GameObject is in Field of View

Archived Forums Questions & Answers
1

I try to calculate if a GameObject is in Field of View of my Camera.

Edit: Becouse if not i want to disable the MeshRenderer of the GameObject.

Is there a buld in function i didnt find till now? Right now im using this code snippet which looks to work right. But im not sure.

Vector3 cameraRelative = _camTransform.InverseTransformPoint(gO.transform.position);
Vector3 screenPos = _cam.WorldToScreenPoint(gO.transform.position);

if (screenPos.x > 0 && screenPos.x < Screen.width && screenPos.y > 0 && screenPos.y < Screen.height && cameraRelative.z > 0)
// The object is in front of the camera
_inView = true;
else
// The object is behind the camera
_inView = false;

2 Answers

2
3

You can just use this:

bool visible = renderer.isVisible

Perfect! Thank you!

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I cheered to fast. I have a little problem. After i disable the rendere. I, not able to Enable it again, because after that renderer.isVisible is always false.

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Why do you need to disable the renderer if it's out of view again? it's not being rendered

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Ahhh! If the renderer is not vissible it will not be rendered at all? So i can use isVisible only for my calculations? I testet it and it look that it works in this way!

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Nice if(AI_Man_Mesh.renderer.isVisible){ Debug.Log("I can see a you mr AI man!!"); } Handy!

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2

There's an option to stop animations if the object is not in view

http://unity3d.com/support/documentation/ScriptReference/Animation-animateOnlyIfVisible.html

Sorry I sayd the wrong thing. I dont use the Animation Class from Unity, instead i using the iTween library. Also i want to disable the MeshRenderer on the GameObjects not in view.

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